The Ba₅CaAl₄O₁₂:Tb³⁺ phosphor was synthesized by high temperature solid state reaction,and its luminescent properties were investigated. The emission spectrum of Ba₅CaAl₄O₁₂:Tb³⁺ excited by 239 nm light shows four major emission peaks locating at 489,543,550,587 and 623 nm corresponding to the 5D4→7F6,5D4→7F5,5D4→7F4 and 5D4→7F3 typical transitions of Tb3+,respectively. The UV excitation spectra indicates that the host absorption is located at about 240 nm. The effect of the molar concentration Tb3+ on the emission intensity is studied. The result shows that the emission spectrum intensity reaches the maximum value when the mole fraction of Tb3+ is 4%. Fluxing H3BO3 and NH4Cl on the sample increases the luminescent intensity in various degree. The emission spectrum intensity increases with increasing the H3BO3 and NH4Cl concentration,and then decreases. Compared with the fluxing H3BO3,the NH4Cl can enhanced the luminescent intensity better.